What is the difference between $0$ and $\vec{0}$?

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If we take the approach underlined by Peano axioms, we get:

$$a + (-a) = 0.$$

Likewise, we can get the same thing in Euclidean plane:

$$|AB| + (-|AB|) = 0,$$

where $A$ and $B$ are points, and $|AB|$ is the length of the line segment $AB$ (thus the "operation" $AB - AB$ has no meaning, as we have not ascribed any attributes to the line segment).

On the other hand,

$$\vec{AB} - \vec{AB} = \vec{AB} + \vec{BA} = \vec{0}.$$

Well, what is the difference between $0$ and $\vec 0$ ? I think that a concrete definition of both should clear my confusion up. I understand that $\vec 0$ cannot be used in the same context as $0$ (because the former arises from the definition of vector), but I still don't have in-depth understanding of the concept of $\vec 0$. In Euclidean plane both $0$ and $\vec 0$ are points, right? So what's the difference then?

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We sometimes write $\vec{0}$ for the zero vector in a vector space to distinguish it from the $0$ inside the field we are working over. For example, you could write that $0\vec{v}=\vec{0}$.

Actually, $0$ can also be used in vector spaces to denote the $\vec{0}$, because algebraically it is the zero element of the underlying abelian group. This is less specific than the notation in the last paragraph though.

In Euclidean plane both $0$ and $\vec{0}$ are points, right?

Well, I wouldn't want to say it that blithely, given the context I mentioned above. In the Euclidean plane, things look like ordered pairs $(a,b)$, and we might say that $\vec{0}=(0,0)$ where the $0$ comes from the underlying field (not the plane.) These ordered pairs are coordinate vectors yes, meaning that they specify a particular point in the plane.

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$\vec{0}$ is a vector while $0$ is a number