I'm weak at math and I need the inverse of this function if it's computable:
$f(t) = A + (-2t^3 + 3t^2)(B-A)$
Note that $A$ and $B$ are constants.
thanks for your help.
2026-03-28 13:27:18.1774704438
what is the inverse of this function
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Cardano-Tartaglia want you to find the cube root of a complex number. (whenever there are three real roots, the cube-root is of a complex number.)
Another option is Newton's Method. Let $$g(t)=6(t-t^2)(B-A)$$
You should run this up to $t_3$ or $t_4$, or until $t$ doesn't change much:
$t_1=1/2\\ t_2=t_1-(f(t_1)/g(t_1))\\ t_3=t_2-(f(t_2)/g(t_2))\\ t_4=t_3-(f(t_3)/g(t_3))$