What is the meaning of a limit as $e^{(n+1) \infty}$ in WolframAlpha?

Question

I inputted the following into WolframAlpha:

lim x to 0 of (cotx)/x^n

And I got

$$\lim_{x \rightarrow 0}{\frac{\cot{x}}{x^n}} = e^{(n+1) \infty}$$

What does this mean?

Answer 1

It probably denotes that the final value of the limit depends on $n$. Specifically, if $n+1 < 0$, then the limit is $\to e^{-\infty} = 0$ while if $n+1 >0$, then the limit is $\to e^{+\infty} = \infty$.