I feel like it accepts either the string {0}, or repeated {10} only. I tried making it have odd/even number of 0s and 1s but it still doesn't work. I know my answer is wrong but I really don't know how to read this one DFA.
(Sorry my english isn't good)
If the accepting states are the double circled ones:
$0$ moves us to an accepting state. Anything after the initial $0$ will move us to the "central state" which is a black hole: we never leave and can no longer reach an accepting state anymore.
Downstairs it's more interesting: $11$ gets us to the black hole, so no accepted string can start with $11$, $10$ does bring is into an accepting state; after that we should have no $0$ but $10$ again to bring us back. $11$ is going to the black hole again.
So I get that $\{0\} \cup 10(10)\ast$ is the accepted language for this DFA.