I posted a question on how to show that point was the barycenter of a triangle. I understood the process of the answer that they gave me, but don't know if the information is enough to show that point was the barycenterI since I don't know much about it. Here would be a drawing of what he basically did did:
He showed that $D$ was the midpoint of $BC$ and that $ \frac {BF}{BE}= \frac {2}{3}$. Would that be enough to show that $F$ is the barycenter?
Also if I have a point in a triangle the splits two lines (coming from two different vertices) into two segments with the proportion $1:2$ is that enough to say that that point is the barycenter?

Draw median $\overline{BE'}$ and let $G = \overline{BE'} \cap \overline{AD} $. Suppose that $E' \neq E$.
Then $BG/BE = BF/BE$, and thus $\triangle FBG \sim \triangle EBE'$. This implies $\angle BGF = \angle BE'E$, or that $\overline{GF} \parallel \overline{E'E}$, which is false since $\overline{GF}$ and $\overline{E'E}$ intersect at $A$.
Thus, $E' = E$, so $\overline{BE}$ is a median. Then $F = \overline{BE} \cap \overline{AD}$ is the barycenter.