Since, $Cov(X, X + 3Y) = Cov(X, X) + 3Cov(X, Y) = V(X) + 3 Cov(X, Y)$
What would $Cov(2X, 4X + 3Y)$ be?
Here's how you can do it:
$$Cov(2X, 4X + 3Y) = 2Cov(X,4X+3Y) = 2Cov(X,4X) + 2Cov(X,3Y) \\ = 8Cov(X,X) + 6Cov(X,Y) = 8V(X)+6Cov(X,Y) \; .$$
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Here's how you can do it:
$$Cov(2X, 4X + 3Y) = 2Cov(X,4X+3Y) = 2Cov(X,4X) + 2Cov(X,3Y) \\ = 8Cov(X,X) + 6Cov(X,Y) = 8V(X)+6Cov(X,Y) \; .$$