Which theorem should be used to solve this question?

162 Views Asked by At

My friend sent me that question and said "another Carnot theorem" is used to solve this question but i couldnt find that theorem. Can you help me?

Additional explanation: $$ \widehat{ABD} = 30^{\circ} $$ $$ \widehat{DBC} = 1^{\circ} $$ $$ \widehat{ACD} = 89^{\circ} $$ $$ \widehat{BAD} = \widehat{DAC} $$ $$ x(\widehat{BCD}) = ? $$

Hard geometry question

1

There are 1 best solutions below

1
On

You should use Ceva's theorem (in trigonometric form -- http://www.cut-the-knot.org/triangle/TrigCeva.shtml)

We have

$\frac{\sin 1^\circ\sin 89^\circ}{\sin 30^\circ\sin x}=1$, i. e.

$sin x = \frac{\sin 1^\circ \cos 1^\circ}{\sin 30^\circ} = 2 \sin 1^\circ \cos 1^\circ=sin 2^\circ$

$x=2^\circ$