
It is difficult to see the picture of the problem. The question is "What are the lengths of AC and AB?" What is given is a right triangle, ABC. Angle B is 30 degrees and BC is 7.0 distance.
The way I solved it was by using the properties of a 30 60 90 degree triangle which I learned from a unit circle. The segment opposite the 30 degree angle is 1/2 the distance of the hypotenuse. And the segment opposite the 60 degree angle is square root of 3 times the length of the side opposite 30 degrees. (I think that's correct). I got it right.
Though, I originally tried to solve the problem though using an equation using proportions. I figured: Alright 90 degrees over 7.0 is proportionate to 30 degrees over x. Thus: 90/7 = 30/x and I solved it. However, I did not arrive at the correct answers. Can someone help me understand why this does not work? Thanks, Paige
As long as it's a 30-60-90 triangle, you can always use the proportions. You're thinking about the wrong proportions, however: the lengths are not exactly proportional to the angles. You'll get to that in trig with law of cosine, but, for now, the sides are proportional to each other in the way presented in the image above. Above is a triangle similar to the one you presented (i.e. angles at the same place) with some variables $a$ to describe the proportions. We know that, in your case, the side that's $2a$ is equal to 7. Hence: $$2a=7$$$$a=3.5$$
Now that we know what $a$ is, we can find the lengths easily. AC is the side opposite of the 30-degree angle and is equivalent to $a$. Therefore, it is 3.5. That already eliminates you down to choices C and D. Then we have AB, which is opposite of the 60-degree angle and is equal to $a\sqrt{3}$. This is approximately equal to $6.1$.
The final answer is, then, D.