In resources like Wikipedia the following equation holds for $k>0$. \begin{equation} \sum_{n=0}^{k} [x^n]=\frac{1-x^{k+1}}{1-x}\hspace{1cm}x\neq1 \end{equation} If you put the right hand side in a limit it holds for $k\geq0$. But why do we rarely show the bounds of the k value and why not put the k in an absolute value on the right hand side (Other than the aversion to absolute values)?
2026-03-29 17:25:25.1774805125
Why in geometric formula definitions do they not exclude the negatives in the domain or use an absolute value?
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2
Your question
is one about conventions and expectations which is a common situation.
For example, to use an authoritative source, the DLMF section 1.2.11 states explicitly
and also in a mouse popup states in reference to DLMF section 1.1 Special Notation that
Notice that in the summation the DLMF decided to use an explicit sum with $\,\cdots\,$ instead of using summation notation. Both choices are valid and, in some cases, both are used for clarity.
A much less popular choice would have been to use a convention such that $$ s_n := \sum_{k=0}^n a_k \quad \text{ where }\quad s_n = s_{n-1} + a_n,\quad s_0=a_0 $$ and which is supposed to be true for all integer $\,n.\,$ For example, your case of $$\sum_{k=0}^n x^k = \frac{1-x^{n+1}}{1-x}\quad\text{ where }\quad x\ne1 $$ is true for all integer $\,n\,$ by this convention and would be assumed as such in this context by this convention without being specifically mentioned explicitly. No need to use absolute value for $n$.
Your further question
is simply because, in the common convention, $\,k\,$ is always assumed to be nonnegative. Therefore, the equation is only assumed to be valid for those $\,k\,$ although it may be valid outside that range using an alternative convention.