In lectures it was said that the fundamental group of the following shape, which we called $X_3$ (why?):
is $\pi_1(X_3, P) \cong \mathbb{Z} * \mathbb{Z} * \mathbb{Z} * \mathbb{Z}$, i.e. the free group on four generators.
Why is this the case?
In lectures it was said that the fundamental group of the following shape, which we called $X_3$ (why?):
is $\pi_1(X_3, P) \cong \mathbb{Z} * \mathbb{Z} * \mathbb{Z} * \mathbb{Z}$, i.e. the free group on four generators.
Why is this the case?
Your space is homotopically equivalent to a wedge sum of $4$ circles. The result now follows from van Kampen.