Why is the inverse of $y=b^x$ $y=\log_b(x)$ instead of $x=\log_b(y)$

47 Views Asked by At

As I understand it, the relationship between $y=b^x$ would be written logarithmically as $\log_b(y)=x$, but I'm watching a video on khan academy where he states the inverse of $y=b^x$ is $\log_b(x)=y$. Is the logarithmic form of an exponential equation not the inverse of that equation?