we know this definition:
Given a binary tree, Width of a tree is maximum of widths of all levels.
Let us consider the below example tree.
1
/ \
2 3
/ \ \
4 5 8
/ \
6 7
For the above tree, width of level 1 is 1, width of level 2 is 2, width of level 3 is 3 width of level 4 is 2.
So the maximum width of the tree is 3.
can we have a binary tree with Height $\theta(n)$ and Width $\theta(n)$
My solution: is YES. for example a binary tree with one-node:
1
am i right?
The answer is no.
the Symbol $\Theta (n)$ is related to Average case for set of (bigger) n. So with one tree you couldn't say the tree with one-node has $\Theta (n)$ in height and width.