Wolfram Alpha - FourierParameters not working with discrete fourier transform

Question

I am trying to calculate the discrete fourier transform using the signal processing convention. The documentation gives the followng example:

Fourier[{1, 2, 3, 4, 5, 6}, FourierParameters -> {1, 1}]

Based on the docs I expected a result like this:

{21, -3 -5.19615i, -3 -1.73205i, -3 -1.73205i, -3 -5.19615i}

Instead, I got:

{
    FourierTransform[1, FourierParameters -> {1, 1}, ω],
    FourierTransform[2, FourierParameters -> {1, 1}, ω], 
    FourierTransform[3, FourierParameters -> {1, 1}, ω],
    FourierTransform[4, FourierParameters -> {1, 1}, ω],
    FourierTransform[5, FourierParameters -> {1, 1}, ω],
    FourierTransform[6, FourierParameters -> {1, 1}, ω]
}

Does anyone know why this isn't working and how I can get around it?

Answer 1

Instead of Wolfram|Alpha use the Wolfram Development Platform and choose "Create a New Notebook". Type in the command

Fourier[{1, 2, 3, 4, 5, 6}, FourierParameters -> {1, 1}]//Chop

in a cell and hit Shift-Enter. The result is

{21.,-3.-5.19615i,-3.-1.73205i,-3.,-3.+1.73205i,-3.+5.19615i}

as you expected.