A is thrice as good as a workman as $B$ and therefore is able to finish a job in $60$ days less than $B$. How much time will they take to finish the same job if they work together?
My attempt:
Let's say that the amount of work done by $B$ in $1$ day = $1 \over B$
As $A$ is $3$ times better than $B$, hence the amount of work done by $A$ in $1$ day=$3 \over B$
The difference in times to complete the same work is $60$ days.
Hence, ${3 \over B} - {1 \over B} = {1 \over 60}$
Solving which gives me B as 120 days and A as 40 days. Working together, they can complete the same job in ${ 1 \over {1 \over 120} + {1 \over 40}}= 30$ days.
But the correct answer, as given in the question, is something else.
What did I do wrong?
I learned how to do this with a table, so let's see if I can format it all correctly here. (Sorry in advance, my LaTex friends)
We know that rate (r)*time (t)=work, and that the work is the same for all jobs.
Rate Time Work A 3r t-60 1Now, we know that their rate together is 4r because rates can be added when they combine their abilities. If we set up a system:-------------------------
B r t 1
-------------------------
Both 4r ? 1
so Then we can fill in our chart and figure out some other stuff.
Rate Time Work A 1/30 30 1Using again our equation:-------------------------
B 1/90(r) 90 1
-------------------------
Both 4/90 x 1
That was a lot of formatting work, so please at least admire it if/when/before editing it.