The area of $\triangle OBF$ is $5$ cm$^2$. $F$ is a point on $OA$ such that $OF = \dfrac9{11}OA$. Work out the area of $\triangle OBA$.
I have tried to solve this problem for a while, and just can't figure out how to do it. Please help.
The area of $\triangle OBF$ is $5$ cm$^2$. $F$ is a point on $OA$ such that $OF = \dfrac9{11}OA$. Work out the area of $\triangle OBA$.
I have tried to solve this problem for a while, and just can't figure out how to do it. Please help.
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Hint: Observe that both $\triangle OBF$ and $\triangle AOB$ have same height on bases $OF$ and $AO$

Here DE is perpendicular for $\triangle DCB$