Write the co-ordinates of E such that the parallelogram ABCE is a rhombus.

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I'm unsure how to do this and it's always in my exams. (The original shape was a triangle and E was originally not a point)

A:(1,0) B:(0,8) C(7,4)

Gradient of AC:2/3

AC equation:2x - 3y - 2 = 0

Coordinates of the midpoint D of AC: 4,2

  • AC is perpendicular to BD

  • ABC is an isosceles

Area of triangle = 26 u

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The diagonals of a rhombus bisect each other at right angles (Proof)

If $O(p,q)$ is the midpoint of $AC, B E$

If $E(h,k)$ $$\dfrac{1+7}2=p=\dfrac{0+h}2$$ and $$\dfrac{0+4}2=q=\dfrac{8+k}2$$