X is any point on AB and the median AD of triangle ABC meets XC at Y.Prove that XY/YC = AX/XB.
2026-04-28 12:41:37.1777380097
X is any point on AB and the median AD of triangle ABC meets XC at Y.Prove that XY/YC = AX/XB
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Let $XE||AD$. Then $$\frac{XY}{YC}=\frac{ED}{DC}=\frac{ED}{DB}=\frac{AX}{AB}\not =\frac{AX}{XB}$$