A field $K$ of order $q=p^r$ contains a subfield $K'$ of order $q'=p^k$ if and only if $k\mid r$.

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I was trying to prove the following theorem:

A field $K$ of order $q=p^r$ contains a subfield $K'$ of order $q'=p^k$ if and only if $k\mid r$.

My attempt at the proof was:

$K'\setminus\{0\}$ is a subgroup of $K\setminus\{0\}$. So, $p^k-1\mid p^r-1$.

From the exponent gcd lemma [$\gcd(a^x-1,a^y-1)=a^{\gcd(x,y)}-1$ when $a,x,y\in\mathbb N,a\geq 2$.]

We have that $k\mid r$.

Is this proof correct? In fact, I'm worried about this particular statement:

$K'\setminus\{0\}$ is a subgroup of $K\setminus\{0\}$.