Advanced Level Geometry prob.

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$ABCD$ is parallelogram. $$m(AEB) = 79°$$ $$m(ABD) = x$$ How do I find $x$? I have tried to find it and got $102°$ but I'm wrong. Thanks for helping.

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Trusting the figure you have $$\begin{cases} 180° - \frac{1}{2} \widehat C - \frac{2}{3} \widehat D = 79°\\ \widehat C + \widehat D = 180°\\ \end{cases}$$ Can you solve this system? Then $x=\widehat C$.

$x=114°$