Hint: Let $u=cx$ and write $v=cx^2$ in terms of $u$.
What I think the answer is:
$y=x^2$ is the same as $(x, x^2)$ therefore, applying $D$ to the equation gives us $(cx, (cx)x=cx^2)$, that is, $y=cx^2$.
Hint: Let $u=cx$ and write $v=cx^2$ in terms of $u$.
What I think the answer is:
$y=x^2$ is the same as $(x, x^2)$ therefore, applying $D$ to the equation gives us $(cx, (cx)x=cx^2)$, that is, $y=cx^2$.
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According to the given hint, $x = \dfrac {u}{c}$.
Expressing v in terms of u, we should have $v = cx^2 = c (\dfrac {u}{c})^2 = \dfrac {u^2}{c}$. Then, $y = \dfrac {x^2}{c}$.