Theorem: The radius of a circle is perpendicular to the tangent at the point of tangency
One particular proof I came across is as follows:
$$\text{The measure of} \: \: \angle CAB \: \: \text{is one half the arc it cuts off. Since the chord is the diameter, the arc is half the circle, so } \angle CAB = \frac{180^{\circ}}{2}$$
However here $180^{\circ}$ is not the length of the arc. It is the measure of the angle that subtends it.
Similarly stated:
The measure of an inscribed angle is half the arc it subtends
It is stated that $\angle ABC = \frac{\frown {AC} }{2}$
But shouldn't it be $2r\angle ABC = \frown AC \implies \angle ABC = \frac{\frown AC}{2r}$
Those quotes are misleading, they make one think that an arc is measured by arc length. But that's not what's going on in this context. Adding a few words to those quotes might clear things up:
You must take care, of course, that these angles measures use the same units: you could use units of degrees; or instead use units of radians.
So, for instance, the angle measure in degrees of a semicircular arc is indeed $180^\circ$, which equals half the angle measure in degrees of the whole circle which is $360^\circ$. And so $\angle CAB$ does indeed have an angle measure in degrees equal to $\frac{180^\circ}{2} = 90^\circ$.