"Cedargrove doesn’t have their own ambulance service; they use the ambulances from two neighbouring villages on opposite sides. If the probability the first ambulance is in use is 14% and the probability the second ambulance is available at any given time is 66%, find the probability that at least one ambulance will be available."
I know the answer to this is roughly 95% but I am unsure how to get there. I originally did 14% x 66%, which equaled 9.24%, which I now realize is wrong. I also tried the P(at least one) = 1 - P(none), but I got 1 - (0.86*0.34) = 70.76%
The wording is (deliberately?) tricky. The probability that both are unavailable is $.14\times .34=0.0476$, so the probability at least one is available is $0.9524$