Bayes' Theorem with multiple random variables

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I'm reviewing some notes regarding probability, and the section regarding Conditional Probability gives the following example:

$P(X,Y|Z)=\frac{P(Z|X,Y)P(X,Y)}{P(Z)}=\frac{P(Y,Z|X)P(X)}{P(Z)}$

The middle expression is clearly just the application of Bayes' Theorem, but I can't see how the third expression is equal to the second. Can someone please clarify how the two are equal?

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We know $$P(X,Y)=P(X)P(Y|X)$$ and $$P(Y,Z|X)=P(Y|X)P(Z|X,Y)$$ (to understand this, note that if you ignore the fact that everything is conditioned on $X$ then it is just like the first example).

Therefore \begin{align*} P(Z|X,Y)P(X,Y)&=P(Z|X,Y)P(X)P(Y|X)\\ &=P(Y,Z|X)P(X) \end{align*} Which derives the third expression from the second.

(However I don't have any good intuition for what the third expression means. Does anyone else?)