Hello,
I've been trying to understand the solution to the problem above. I am confused as to how the solution can declare that angle DQE = (arc BC + arc DE)/2 and angle CPQ = (arc CD - arc BC)/2. I'd really appreciate an explanation.
Thanks ^_^
Hello,
I've been trying to understand the solution to the problem above. I am confused as to how the solution can declare that angle DQE = (arc BC + arc DE)/2 and angle CPQ = (arc CD - arc BC)/2. I'd really appreciate an explanation.
Thanks ^_^
Copyright © 2021 JogjaFile Inc.
See this article. That's a generalization of Thales Theorem known as the inscribed angle theorem.