Closed form of solution of functional equation

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Consider the functional equation

$f(x)+f(\frac{x^2}{2})=x \mspace{10mu},\mspace{10mu}0<x<2$ .

$x\mapsto \frac{x^2}{2}$

$f(x)+f(\frac{x^2}{2})=x$

$f(\frac{x^2}{2})+f(\frac{x^4}{8})=\frac{x^2}{2}$

$f(\frac{x^4}{8})+f(\frac{x^8}{2^7})=\frac{x^4}{2^4}$ ...

$f(x)=x-\frac{x^2}{2}+\frac{x^4}{16}...=\sum_{k=0}^{\infty}(-1)^{(n+1)}(x/2)^{(2^n)} $

Can one get closed form of the series?