Given:
$P_x(x)=c\frac{1 } {x^2} $ for $-\infty<x<\infty$.
$c$ is constant.
Need to compute the expected value $E(x)$.
So I know that the sum is not converge absolutely, does it means also the expected value $E(x)$ divergent?
2026-04-07 08:04:26.1775549066
Computing expected value $P_x(x)=c\frac{1 } {x^2} $ for $-\infty<x<\infty$
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Your problems start before you get to the expected value. This density is not normalized (and not normalizable), so it’s not the density of a random variable whose expectation you could try to compute.