Conditional probability doubt: Good drivers, bad drivers, accidents, Blitzstein

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I am really stuck in part 3 of this problem.

user465188, Question on Independence of Events, URL (version: 2018-09-28): Question on Independence of Events

Nowhere is it mentioned that P(A|G)=P(A), that is A and G are independent. What is given is that $(A \cap B)$ and G are independent events. So, how does one derive that A and G are independent?