Conditional probability with two dice

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I am trying to solve a problem. Two dice (1 and 2) are rolled. Let's define the following events $$ A_{1} = \text{the result of dice 1 is even}\\ A_{2} = \text{the result of dice 2 is even} \\ A_{3} = \text{both dice give the same result} \\ $$ I need to compute $P(A_3 | A_1 \cap A_2)$ and $P(A_{1} \cup A_{2} \cup A_{3}^{c})$. My calculations are the following $$ P(A_3 | A_1 \cap A_2) = \frac{P(A_3 \cap A_1 \cap A_2) }{ P(A_1 \cap A_2)} = \frac{3/36}{3^2/36} = 1/3 $$

\begin{align*} P(A_{1} \cup A_{2} \cup A_{3}^{c}) & = 1 - P(A_1^c \cap A_2^c \cap A_3) \\ & = 1 - P(A_3| A_2^c \cap A_1^c)P(A_2^c \cap A_1^c) \\ &= 1 - \frac{1}{3} \cdot \frac{3^2}{36} \\ & = \frac{11}{12} \end{align*} but I don't know if it's correct. Could someone corroborate or help me?

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They are correct, if you are in doubt you can just write explicitly the events and you can compare them to the results.