Convergence in distribution for $\frac{Y}{\sqrt{\lambda}}$

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Given a sequence of independent r.v's $\{X_n\}_{n\geq 1}$ such that

$P(X_n=x)=\frac{1}{2}$ if $x=-1$ and/or $x=1$

Let $N\in Po(\lambda)$ be independent of $\{X_n\}_{n\geq 1}$ and we set that $Y=X_1+X_2+\dots+X_N$

One have to show that $\frac{Y}{\sqrt{\lambda}}$ converges in distribution to $N(0,1)$ as $\lambda$ goes to infinity.

How can this be shown? I have been thinking of some kind of use of central limit theorem but I don't get any idea for how to use it to show the convergence...