celsius=5/9(fahrenheit− 32)
if the standard deviation of a random sample containing 14 people is 0.9 degrees farenheit, what's the variance in celsius?
I have tried 5/9(0.18-32) but I get a negative number for variance which is obviously wrong. I used 0.18 because 0.9^2=0.18.
Shifting the data does not change the deviations at all. So the subtraction is completely irrelevant to this problem.
Multiplying the data by $\frac59$ multiplies the standard deviation by $\frac59$.
Once you know the standard deviation in Celsius, it's not difficult to find the variance.