My question
The solution for first part
$$L=(aq+1-a)x1x2+\lambda (y-(a(p1+c)+(1-a)p1)x1-x2p2)$$
As a result after FOCs
$$x1=\frac {y}{2(a(p1+c)+(1-a)p1)}$$
$$x2={y\over 2*p2}$$
The solution for the second part
$$\lambda (a(p1+c)+(1-a)p1)= (aq+1-a)x2$$
$$\lambda (a(p1+c)+(1-a)p1)= (aq+1-a){y\over 2*p2}$$
$$a(qy-y-2p2\lambda c)=2p2\lambda p1-y$$
$$a={2p2\lambda p1-y\over a(qy-y-2p2\lambda c)}$$
I would like to ask for the second part.
The first part solution is just informative. Please don’t interest on its solution. But for the second part, I have tried to derive alpha. But, I guess this result for the value of alpha is wrong. Please tell me what you think about deriving of alpha. How can I do it if it is wrong?