If $L : C^2[a,b] \rightarrow C^0[a,b] $ is s.t. $L y(t) = \ddot y(t) +p \dot y + q y(t) $ and $L$ is invertible then $L^{-1}$ has at most countable eigenvalues and they accumulate in $0$.
Why countable? And why should they accumulate in $0$?
2026-03-26 12:32:18.1774528338
Eigenvalues of differential operator
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