Expansion of $\frac{1}{(1 - e^{-x})}$

Question

As Taylor's series give $e^x = 1+x+\frac{x^2}{2!}+\frac{x^3}{3!}+...$

Similarly, can someone please help me to find expansion of the term $\frac{1}{(1 - e^{-x})}$? Where $0 < e^{-x} < 1$

Thank you.