Expectation of a Levy process with exponiantially distributed time

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I am reading about Levy processes and am having trouble to understand the following:

Let $X$ be a subordinated Levy Process on ($\Omega$, $\mathcal{F}$, $\mathbb{P}$), and let $\tau$ = $\tau\left(q\right)$ be exponentially distributed with $q>0$.

My question is, why is it that

$\mathbb{E}\left[X_{\tau}\right] = \int_{0}^\infty qe^{-qt} \mathbb{E}\left[X_{t}\right] dt$

And likewise,

$\mathbb{P}\left[X_{\tau} \in dy \right] = \int_{0}^\infty qe^{-qt} \mathbb{P}\left[X_{t} \in dy\right] dt$

I do understand the intuition behind it, however I cannot seem to work out the mathematics behind it starting from the definitions of expectations and probability distributions as integrals, as my $dt$ always disappears.

Any help would be much appreciated.

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This is a generic probability question. The idea is that $$ \mathbb{E}[X] = \int_{D(Y)} \mathbb{E}[X|Y=y]f_Y(y)\,\mathrm{d}y $$ where $D(Y)$ is the domain of $Y$. In this case, you take $Y=\tau$ and we have that the density of $f_{\tau}(y) = qe^{-qy}$.