Let $K$ be a field with characteristic $p>0$ and $M=K(X,Y)$ the field of rational functions in 2 variables over $K$. We consider the subfield $L=K(X^p,Y^p)\subset M$.
Show that $[M:L]=p^2$.
I guess I need the property that $[K(x):K(x^n)]=n$, which we showed already. But I actually do not know how to use it here. I can not work well with that field in 2 variables..
Recall that for some field $J$ so that $L \subset J \subset M$ you have that the degree of the extension $L \subset M$ is the product of the degrees of the extensions $L \subset J $ and $ J \subset M$.
Use this for example with $J=K(X^p,Y)$, applying the result you know twice.