I think the flaw is in assuming that $N^{2} \in \mathbb{N}$, but I don't know.
2026-03-27 02:37:43.1774579063
Bumbble Comm
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Find the flaw in this proof that $1$ is the greatest natural number
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Bumbble Comm
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The flaw is in assuming there is a largest natural number. Assuming that, one can also show that number is $2$, or $17$, or $-3.5$, all at the same time. Ex falso quodlibet.
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The proof is logically correct, and leads to a contradiction (we know that $1<2$). Thus it is a valid proof that there is no greatest natural number.