Below is a truth table I made for this expression: (p → q) ∧ (p ∨ q). My question is, is there a simple, basic operation between two logic variables that have the same exact outcome as the expression I got from this truth table and expression?

Below is a truth table I made for this expression: (p → q) ∧ (p ∨ q). My question is, is there a simple, basic operation between two logic variables that have the same exact outcome as the expression I got from this truth table and expression?

On
I agree with the other answers but offer a different perspective.
First of all, re
"...is there a simple, basic operation between two logic variables"
based on the above, it is unclear whether the answer I am offering is appropriate.
Anyway
$(p \rightarrow q)$ is logically equivalent to $[(\neg p) \vee q].$
Therefore, the statements are converted to
$[(\neg p) \vee q]$
and
$(p \vee q)$.
${ } { } q { } { } { { } } { } { } { } { } $