How can we find $$L=\limsup_{n\to\infty}\sum_{k=0}^n(-1)^k|\sin k|,$$ where $|\cdot|$ denotes the absolute value of $\cdot$?
According to this answer, we can see the limit does exists. Unfortunately, this answer is not constructive. It does not provide a method to find the value of the limit.
Since $(-1)^{2k+1}|\sin k|<0$,
$$L=\limsup_{n\to\infty}\sum_{k=0}^{2n}(-1)^k|\sin k|\\
=\limsup_{n\to\infty}\sum_{k=1}^{n}\Big(|\sin (2k)|-|\sin (2k-1)|\Big)$$
I noticed that if we can estimate $\sum_{k=1}^{n}|\sin (xk)|$ to $o(1)$ term, the problem will be solved, but I have no idea how to reach it.
Hint :
Using Fourier Series for $|\sin x|$, it is :
$$|\sin x|=\sum_{m=0}^\infty c_m\cos (mx) $$