Find the area of the region bounded by the graphs of $y = |x|$, $y = |x| + 3$, and $y = 5 - |x|$.
I got $\left(\dfrac{5\sqrt2}2\right)^2$, but this is incorrect.
I don't really understand what the problem means when they say "bounded" because there is a small region, and a big region that could both be interpreted as the "bounded region."
Any solution + clarification on what this bounded region is? Thanks.

I think it's the area of the square bounded by $(0,0), (\dfrac52,\dfrac52), (0,5), $ and $(-\dfrac52,-\dfrac52)$
minus the area of the square bounded by $(0,3),(1,4), (0,5), $ and $(-1,4)$.
(That small square is bounded by only two of the three graphs.)
The area of a square with diagonal length $d$ is $\dfrac{d^2}2$.
Can you use this information to get the correct answer?