Find the area enclosed by the graph of the parametric equations: \begin{align*} x & = 6 \cos(t) \sin(t), \\ y & = 6 \cos^2(t). \end{align*}
Should I multiply the top equation by $-\cos(t)$? Then I could do like, $y-x = 30 \cos ^2(t) \sin^2(t)$?
2026-04-29 19:05:44.1777489544
Finding the area on a graph defined by parametric equations
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We have $x^2+(y-3)^2=9$, which gives the answer: $9\pi$.