Finding the size of an obtuse angle

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triangle ABC

In the diagram, $|BX|$ is the bisector of angle $ABC$ and $|CX|$ is the bisector of angle $ACB$, if angle $A=68$. Find the size of the obtuse angle $BXC$.

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Hint. $\frac{1}{2}\angle B+ \frac{1}{2}\angle C=\frac{1}{2}(180-68)$.