Geometrical derivation of angle addition formulae in hyperbolic trigonometry

599 Views Asked by At

The angle addition formulas in “regular” trigonometry state that

$\sin(\alpha+\beta)=\sin\alpha\cos\beta + \cos\alpha\sin\beta$

and

$\cos(\alpha+\beta)=\cos\alpha\cos\beta - \sin\alpha\sin\beta$

It is fairly straightforward and easy to derive these formulas from a figure like this:

angle addition proof

It is also easy to prove it using:

$\cos(x) = \frac{e^{ix} + e^{-ix}}2$

and

$\sin(x) = \frac{e^{ix} - e^{-ix}}{2i}$

Similar relations hold for the hyperbolic trig functions, namely

$\sinh(\alpha+\beta)=\sinh\alpha\cosh\beta + \cosh\alpha\sinh\beta$

$\cosh(\alpha+\beta)=\cosh\alpha\cosh\beta + \sinh\alpha\sinh\beta$

which again can be computed using

$\cosh(x) = \frac{e^{x} + e^{-x}}2$

$\sinh(x) = \frac{e^{x} - e^{-x}}2$

How would one prove the angle sum formulas for the hyperbolic functions from their geometric definition?