I am in need of a way to represent the sum
$1! + 2! + 3! + 4! = 1 + 2 + 6 + 24 = 33$
in a geometrical way. What I mean by this is that for example, the sum
$1^2 + 2^2 + 3^2 + 4^2 = 1 + 4 + 9 + 16 = 30$
can be represented geometrically as a pyramid with layers consisting of 1, 4, 9 and 16 pieces respectively a regular manner. Image from Wikipedia to illustrate the geometrical construction of the square numbers.
I have tried to find such a regular pattern to construct a geometrical shape from the factorial numbers, but to no avail. How could this be done?
Also, a follow up question: Is there a way to represent the factorial numbers up to an arbitrary number $n!$, instead of ending at $4!$ as stated in this question above? (less important, but interesting nonetheless)
Thanks in advance!
EDIT: The probably most important part is that the 1, 2, 6 and 24 are discrete and somewhat separated from each other, kind of like the different layers in the comparison between te sum of squares (see linked image above).
The only idea I could come up with was counting the number of vertices in a tree graph that had branching ratios of $2, 3, 4, \ldots$, so that the number of vertices on each level were $1!, 2!, 3!, 4!, \ldots$.
If you need more layers ($n=6$), you might want a different layout (thanks to @HenrikSchumacher):
Radial embedding is particularly elegant and helpful too ($n=6$):
Perhaps such a three-dimensional representation would be appropriate:
The answer to your question "Also, a follow up question: Is there a way to represent the factorial numbers up to an arbitrary number n!, instead of ending at 4! as stated in this question above?" is:
$$\sum\limits_{n=1}^k n! = (-1)^{k+1} \Gamma (k+2) \text{Subfactorial}[-k-2]-\text{Subfactorial}[-1]-1$$