Question

Extension of field, $\Bbb{R}(i \pi) = \Bbb{C} $

score 65 · Answer 1 · 2026-02-22 19:55:17

65

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Extension of field, $\Bbb{R}(i \pi) = \Bbb{C} $

Published on 22 Feb 2026 - 19:55

score 109 · Answer 2 · 2026-02-22 21:27:56

109

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Is it true that evaluating a polynomial with integer coefficients at $e$, uniquely defines it?

Published on 22 Feb 2026 - 21:27

score 415 · Answer 3 · 2018-02-14 18:39:32

415

Views

Polynomial root of algebraic number

Published on 14 Feb 2018 - 18:39

score 377 · Answer 4 · 2018-03-03 22:05:17

377

Views

If $\mathcal{O}_{\Bbb{Q}(\sqrt{d})}$ has class number $2$ or higher, does that mean $\sqrt{d}$ is irreducible but not prime?

Published on 03 Mar 2018 - 22:05

score 133 · Answer 5 · 2018-03-04 12:03:50

133

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Is $5^{1/5} - 3\cdot i$ algebraic?

Published on 04 Mar 2018 - 12:03

score 68 · Answer 6 · 2018-03-31 13:04:08

68

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Super Algebraic Numbers?

Published on 31 Mar 2018 - 13:04

score 58 · Answer 7 · 2018-04-03 11:51:01

58

Views

The maximal real algebraic field

Published on 03 Apr 2018 - 11:51

score 518 · Answer 8 · 2018-04-08 08:10:52

518

Views

One of the conjugates of an algebraic integer must have absolute value $\geq$ 1

Published on 08 Apr 2018 - 8:10

score 32 · Answer 9 · 2018-04-08 11:57:06

32

Views

To find the minimal polynomial and to show that (1-i) is an associate of (1+i) in given set

Published on 08 Apr 2018 - 11:57

score 219 · Answer 10 · 2018-04-08 16:16:50

219

Views

proof verification $\frac{3+2\sqrt{6}}{1-\sqrt{6}}$ is an algebraic integer

Published on 08 Apr 2018 - 16:16

score 265 · Answer 11 · 2018-04-16 09:50:18

265

Views

$\sin(2\pi q)$ is algebraic over $\mathbb{Q}$

Published on 16 Apr 2018 - 9:50

score 524 · Answer 12 · 2018-05-05 20:57:28

524

Views

How does knowing that $\sqrt{7}\notin\mathbb{Q}(e^{2\pi i/7})$ help construct this character table?

Published on 05 May 2018 - 20:57

score 82 · Answer 13 · 2018-05-11 22:25:18

82

Views

Polynomial over a field whose power has coefficients in the ring of algebraic integers.

Published on 11 May 2018 - 22:25

score 672 · Answer 14 · 2018-05-16 09:10:18

672

Views

determine the degree of $2+\sqrt3$ over $\Bbb Q$

Published on 16 May 2018 - 9:10

score 219 · Answer 15 · 2018-05-21 12:26:25

219

Views

Is every algebraic number smallest root of a polynomial with integer (or rational) coefficients?

Published on 21 May 2018 - 12:26

List Question

Extension of field, $\Bbb{R}(i \pi) = \Bbb{C} $

Is it true that evaluating a polynomial with integer coefficients at $e$, uniquely defines it?

Polynomial root of algebraic number

If $\mathcal{O}_{\Bbb{Q}(\sqrt{d})}$ has class number $2$ or higher, does that mean $\sqrt{d}$ is irreducible but not prime?

Is $5^{1/5} - 3\cdot i$ algebraic?

Super Algebraic Numbers?

The maximal real algebraic field

One of the conjugates of an algebraic integer must have absolute value $\geq$ 1

To find the minimal polynomial and to show that (1-i) is an associate of (1+i) in given set

proof verification $\frac{3+2\sqrt{6}}{1-\sqrt{6}}$ is an algebraic integer

$\sin(2\pi q)$ is algebraic over $\mathbb{Q}$

How does knowing that $\sqrt{7}\notin\mathbb{Q}(e^{2\pi i/7})$ help construct this character table?

Polynomial over a field whose power has coefficients in the ring of algebraic integers.

determine the degree of $2+\sqrt3$ over $\Bbb Q$

Is every algebraic number smallest root of a polynomial with integer (or rational) coefficients?

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