This is the solution given in my book but it is incomplete. What will be the next steps to complete the solution .
Edit- After simplifying the problem I now have to prove this inequality . ((x+y+z)^2)>=6xyz
How do i prove this inequality ?
2026-02-23 08:19:31.1771834771
Help me complete the solution to a geometry problem
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1
Each of the terms in the square brackets are the type $a+1/a$. For example, in the first one $$a=\frac xy\\\frac1a=\frac yx$$ You can use AM-GM inequality$$\frac{a+\frac1a}2\ge\sqrt{a\cdot \frac1a}\\a+\frac1a\ge 2$$ The equality happens when $a=1/a$ or $a=1$. Putting it all together $$\left[\frac xy+\frac yx\right]+\left[\frac yz+\frac zy\right]+\left[\frac zx+\frac xz\right]\ge 2+2+2=6$$ You get $6$ when $x=y=z$.