Note that for non-negative integer $n$,
$$
n! = 1 \times 2 \times \ldots \times n = \prod_{k=1}^n k.
$$
If you want to write $n!$ using a sum-like expression, note that
$$
\ln(n!) = \ln\left(\prod_{k=1}^n k \right)
= \sum_{k=1}^n \ln k,
$$
so
$$
n! = \exp\left(\sum_{k=1}^n \ln k\right),
$$
but not sure this is what you are looking for.
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$n!$ involves the multiplication of subsequent terms, rather than an addition, and therefore it is a product rather than a sum.
Therefore, we would typically use product notation, signified by $\prod$ as opposed to $\sum$.
Note that for non-negative integer $n$, $$ n! = 1 \times 2 \times \ldots \times n = \prod_{k=1}^n k. $$ If you want to write $n!$ using a sum-like expression, note that $$ \ln(n!) = \ln\left(\prod_{k=1}^n k \right) = \sum_{k=1}^n \ln k, $$ so $$ n! = \exp\left(\sum_{k=1}^n \ln k\right), $$ but not sure this is what you are looking for.