How can $x = \frac{b}{\ln(x + a)}$ be solved for $x$?

Question

I've solved $x = \ln(x + a)$ by $x = -W(-e^{-a}) - a$, so I suspect that this will also involve the Lambert W function.

However, I've been unable to make any progress due to the $x + a$, but without it I have solved it by:

$x = e^{W(b)}$