Suppose $y=f(x)$ is symmetric in the line $ax+by+c=0$.
Then what is the corresponding line of symmetry for the following ?
- $y=df(x)$ and
- $y=f(dx)$
I guessed that it'd be
- $ax+by/d+c=0$ and
- $adx+by+c=0$
But my guess is wrong: $y=1/x$ has lines of symmetry $y=x$ and $y=-x$. So does $y=2/x$. (In particular, contrary to my above guess, $y=2/x$ doesn't have lines of symmetry $y=2x$ and $y=-2x$.)