I have the central limit theorem exercise solved but the normal distribution not. i want to compare the means and now I am stucked.
the exercise is a discrete random variable modelling in a table with his $E(x)$, population mean and standart deviation. after that I have to run with $4896$ samples. all good the sum and average.
but i dont know how to compare this mean with the normal distribution. anyone knows?
If you take the sample mean of each of your $4896$ samples, they should form a sampling distribution that is normally distributed with mean $\mu$ with $\mu$ being the population mean and standard deviation $\sigma/\sqrt n$ with $\sigma$ being the population standard deviation. That is, each of your samples has lots of observations in it. Once you take the average of the observations in each sample, and plot the resulting 4896 sample means, they should form an approximately normal distribution with aforementioned mean and standard deviation.