Say I have a dice.
Say I suspect that the dice is unfair with probability 75 % with probabilities $p_1, ..., p_6$ that are NOT all equal to 1/6.
However, with 25 % probability, the dice is actually fair and the probabilities are indeed 1/6.
I have two questions:
- What is the mean and variance of this dice's outcomes?
- Are there different ways of defining what I meant by "fake with 75 % probability" and do those different ways lead to different answers? For example, maybe the die is EITHER fake OR real, and I don't know which one it is .... that is one way to define it. OR maybe the die is BOTH fake AND real, and it switches between these two states every time I throw it. This definition is different, but does it give the same answer? Are there other definitions that make sense?
You'd have to calculate it based on $p_i$, for instance on the average one would do: $$E(X) = \sum_{k=1}^6 k \cdot \left(\frac{3}{4}p_1 + \frac{1}{4}\cdot\frac{1}{6}\right) = \frac{3}{4}E(X|\text{fake}) + \frac{1}{4}E(X|\text{real}) $$ The equivalent way to see this question that would more intuitively work is saying you randomly choose a dice out of 4, 3 of which are identical but unfair with probabilities $p_i$, and $1$ is a fair dice, if the chance of an unfair dice were lower one could estimate the mean and variance well enough, but with a $\frac{3} {4}$ that a die can go from rolling straight sixes to rolling straight 1 means the range there is too big to get anything meaningful, in fact: $$\frac{13}{8}\le E(X)\le \frac{43}{8}$$